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Lowpass Filter |
To determine the crossover frequency a certain amount of inductance will give you, use the formula:
RL/(6.283 x L) = F |
Explanation of Terms RL - is the impedance of the load (speaker) you will be using. L - is the inductance value (in Henries) - to convert to Henries divide the value shown on the inductor in mH by one thousand. F - is the crossover frequency you will get. |
| by frequency |
| Crossover Frequency (Hertz) |
inductance mH (milliHenry) |
| 8 Ohms |
4 Ohms |
2 Ohms |
| 80 |
15.92 |
7.96 |
3.98 |
| 100 |
12.73 |
6.37 |
3.18 |
| 120 |
10.61 |
5.31 |
2.65 |
| 150 |
8.49 |
4.24 |
2.12 |
| 200 |
6.37 |
3.18 |
1.59 |
| 280 |
4.55 |
2.24 |
1.14 |
| 400 |
3.18 |
1.59 |
0.8 |
| 600 |
2.12 |
1.06 |
0.53 |
| 800 |
1.59 |
0.8 |
0.4 |
| 1000 |
1.27 |
0.64 |
0.32 |
| 1200 |
1.06 |
0.53 |
0.27 |
| 2000 |
0.64 |
0.32 |
0.16 |
| 4000 |
0.32 |
0.16 |
0.08 |
| 5000 |
0.25 |
0.13 |
0.06 |
| 6000 |
0.21 |
0.11 |
0.05 |
| 8000 |
0.16 |
0.08 |
0.04 |
| 10000 |
0.13 |
0.06 |
0.03 |
| 12000 |
0.11 |
0.05 |
0.03 |
| by inductor |
| inductance mH (milliHenry) |
Crossover Frequency (Hertz) approximate |
| 8 Ohms |
4 Ohms |
2 Ohms |
| 0.1 |
12733 |
6366 |
3183 |
| 0.2 |
6366 |
3183 |
1592 |
| 0.27 |
4716 |
2358 |
1179 |
| 0.3 |
4244 |
2122 |
1061 |
| 0.33 |
3858 |
1929 |
965 |
| 0.4 |
3183 |
1592 |
796 |
| 0.5 |
2547 |
1273 |
637 |
| 0.6 |
2122 |
1061 |
531 |
| 0.7 |
1819 |
909 |
455 |
| 0.8 |
1592 |
796 |
398 |
| 0.9 |
1415 |
707 |
354 |
| 1.0 |
1273 |
637 |
318 |
| 1.2 |
1061 |
531 |
265 |
| 1.8 |
707 |
354 |
177 |
| 2.0 |
637 |
318 |
159 |
| 2.2 |
579 |
289 |
145 |
| 2.7 |
472 |
236 |
118 |
| 3.0 |
424 |
212 |
106 |
| 3.3 |
386 |
193 |
96 |
| 4.0 |
318 |
159 |
80 |
| 4.7 |
271 |
135 |
68 |
| 5.0 |
255 |
127 |
64 |
| 6.0 |
212 |
106 |
53 |
| 7.0 |
182 |
91 |
45 |
| 8.0 |
159 |
80 |
40 |
| 9.0 |
141 |
71 |
35 |
| 10.0 |
127 |
64 |
32 |
| 12.0 |
106 |
53 |
27 |
| 15.0 |
85 |
42 |
21 |
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